SOLUTION: Use substitution to solve each system of equations. a+b+c=6 3a-b+c=8 2b=c

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Question 100335This question is from textbook Algebra 2
: Use substitution to solve each system of equations.
a+b+c=6
3a-b+c=8
2b=c This question is from textbook Algebra 2

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
C=2B
A+B+2B=6 OR A+3B=6
3A-B+2B=8 OR 3A+B=8 NOW MULTIPLY THIS EQUATION BY -3 & ADD THE LAST 2 EQUATIONS.
THIS STEP IS NECESSARY TO ELIMINATE THE B TERM SO WE CAN SOLVE FOR THE A TERM.
A+3B=6
-9A-3B=-24
-----------------------
-8A=-18
A=-18/-8
A=2.25 ANSWER.
2.25+3B=6
3B=6-2.25
3B=3.75
B=3.75/3
B=1.25 ANSWER.
C=2*1.25
C=2.5 ANSWER.