SOLUTION: Please help and show all steps and work.Thanks A chemist has three different acid solutions. The first acid solution contains 20% acid, the second contains 30% and the third con

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: Please help and show all steps and work.Thanks A chemist has three different acid solutions. The first acid solution contains 20% acid, the second contains 30% and the third con      Log On


   

Question 1001675: Please help and show all steps and work.Thanks
A chemist has three different acid solutions. The first acid solution contains 20% acid, the second contains 30% and the third contains 75%. He wants to use all three solutions to obtain a mixture of 64 liters containing 50% acid, using 2 times as much of the 75% solution as the 30% solution. How many liters of each solution should be used?

My answers I came up with is 34,65,29.2
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Variables x, y, z for low, medium, high conc. materials.
system%28x%2By%2Bz=64%2Cz%2Fy=2%2C%2820x%2B30y%2B75z%29%2F64=50%29
Simplify the system to something convenient or comfortable.
system%28x%2By%2Bz=64%2Cz=2y%2C4x%2B6y%2B15z=640%29

Obvious substitution for z.
highlight%28system%28x%2B2y=64%2Cx%2B36y=640%29%29
Using elimination subtracting the '640' equation from the '64' equation,
highlight_green%28y=288%2F17=highlight%2816.94%2Aliters%29%29 for the 30% material.

You can determine x for the 20% material and the z for the 75% material yourself.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Please help and show all steps and work.Thanks
A chemist has three different acid solutions. The first acid solution contains 20% acid, the second contains 30% and the third contains 75%. He wants to use all three solutions to obtain a mixture of 64 liters containing 50% acid, using 2 times as much of the 75% solution as the 30% solution. How many liters of each solution should be used?

My answers I came up with is 34,65,29.2
Sorry, but that's incorrect!

Amount of 20% acid solution to mix: highlight_green%2816%29 L

Amount of 30% acid solution to mix: highlight_green%2816%29 L

Amount of 75% acid solution to mix: highlight_green%2832%29 L