SOLUTION: hi. i need help. it say's that you need write it in standard form (Ax+By=C). this is what i have done so far. 1.(-4,1);(-2,-1) y-2=-1-2/1-(-4)(x-(-4)

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: hi. i need help. it say's that you need write it in standard form (Ax+By=C). this is what i have done so far. 1.(-4,1);(-2,-1) y-2=-1-2/1-(-4)(x-(-4)       Log On


   



Question 61234: hi. i need help.
it say's that you need write it in standard form (Ax+By=C).
this is what i have done so far.
1.(-4,1);(-2,-1)
y-2=-1-2/1-(-4)(x-(-4)

Found 2 solutions by tutorcecilia, funmath:
Answer by tutorcecilia(2152) About Me  (Show Source):
You can put this solution on YOUR website!
(-4,1);(-2,-1) [Find the slope of the line]
m=(y1-y2)/(x1-x2) [use the slope formula]
m=(1-(-1))/(-4-(-2)) [plug-in the values and solve]
m=2/-2=-1
.
Method #1: Use the point-slope form
(y-y1)=m(x-x1) [formula for the point-slope form of a line]
(y-1)=(-1)(x-(-4)) [plug-in the values and solve]
y-1=-x-4 [isolate the variables]
y=-x-4+1
y=-x-3
x+y=-3 [Standard Form of a line]
.
Method #2: Use the slope-intercept form
y=mx+b [slope-intercept form of a line]
1=(-1)(-4)+b [plug-in the values and solve for b]
1=4+b
1-4=b
-3=b [plug-in the slope and y-intercept back into the formula]
y=mx+b
y=-1x-3 [isolate the variables]
x+y=-3 [Standard Form of a line]


Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
write it in standard form (Ax+By=C).
this is what i have done so far.
1.(-4,1);(-2,-1)
I can't follow what you've done, so I'm going to start from scratch. I assume that you have been given these two points and are being asked for the equation of the line in standard form.
In order to write the equation of a line, you need a point and a slope. So we need a slope.
To find the slope when given two points, we use the slope formula:highlight%28m=%28y2-y1%29%2F%28x2-x1%29%29, m=slope, (x1,y1) and (x2,y2) are the given points.
(x1,y1)=(-4,1) and (x2,y2)=(-2,-1)
m=%28-1-1%29%2F%28-2-%28-4%29%29
m=-2%2F%28-2%2B4%29
m=-2%2F2
m=-1
Now we can use the point-slope formula to find the equation of the line:highlight%28y-y1=m%28x-x1%29%29, m=slope and (x1,y1) is a given point.
m=-1 and (x1,y1)=(-4,1)
y-1=-1%28x-%28-4%29%29
y-1=-1%28x%2B4%29
y-1=-x-4
x%2By-1=x-x-4
x%2By-1=-4
x%2By-1%2B1=-4%2B1
highlight%28x%2By=-3%29