SOLUTION: Solving for...
4x-3y = 10
x+4y = 7
Using any methood...
Solution: x = 3.21052631578947, y = 0.947368421052632
However (1, -2) also works why?
How can I solve this system
Algebra ->
Coordinate Systems and Linear Equations
-> SOLUTION: Solving for...
4x-3y = 10
x+4y = 7
Using any methood...
Solution: x = 3.21052631578947, y = 0.947368421052632
However (1, -2) also works why?
How can I solve this system
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Question 610133: Solving for...
4x-3y = 10
x+4y = 7
Using any methood...
Solution: x = 3.21052631578947, y = 0.947368421052632
However (1, -2) also works why?
How can I solve this system and yeild the possible result (1, -2)?
Hi, Re:Your TY
(1, -2) 4x-3Y=10 or 4*1+3*2=10 4+6=10 Yes
x+4y=7 or 1+4*(-2)=7 1+(-8)=7 No: -7 ≠ 7
Might Check Your Sign in EQ II: would yield the solution (1,-2) , y = -2 and x = 1
I. 4x-3y = 10
II. x+4y = 7 ||Signs SO important to the Solution
4x-3y = 10
-4x-16y = -28
-19y = -18
y = 18/19 = 0.947368421052632 and x = 3.21052631578947
(1,-2) is a Pt on the fist line, not the 2nd line. The Solution for this system
of Two EQ, is as You found: x = 3.21052631578947, y = 0.947368421052632