Question 481338: Four family members Tom, Melanie, Bob and Irene have a collective age of 150 years. Melanie is one third Tom’s age and Bob’s age is twice Melanie’s. Irene’s age is as much as Tom’s and Melanie’s put together. What is each person age? Solve by any convenient algebraic method. How would you check your solution?
I've got the answer: tom=45, melanie=15, bob=30, irene=60 but i could not show the steps or solution. will you do it for me?
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Four family members Tom, Melanie, Bob and Irene have a collective age of 150 years. Melanie is one third Tom’s age and Bob’s age is twice Melanie’s. Irene’s age is as much as Tom’s and Melanie’s put together. What is each person age? Solve by any convenient algebraic method. How would you check your solution?
**
let x=Tom's age
x/3 =Melanie's age (1/3 Tom's age)
2x/3=Bob's age (twice Melanie's age)
(x+x/3) =Irene's age (Tom and Melanie ages)
..
x+x/3+2x/3+x+x/3=150
3x+x/3=150
9x+x=450
10x=450
x=45 (Tom's age)
45/3=15 (Melanie's age)
2*15=30 (Bob's age)
45+15=60 (Irene's age)
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