SOLUTION: Alex has 95 cents in dimes and nickels. The total number of coins is 1 more than twice the number of dimes. How many coins of each type does Alex have? I can not figure out the

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: Alex has 95 cents in dimes and nickels. The total number of coins is 1 more than twice the number of dimes. How many coins of each type does Alex have? I can not figure out the       Log On


   

Question 364485: Alex has 95 cents in dimes and nickels. The total number of coins is 1 more than twice the number of dimes. How many coins of each type does Alex have?
I can not figure out the two equations.
I know that one is Dx + Ny = 95
Found 2 solutions by Fombitz, ewatrrr:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Alex has D dimes and N nickels.
The total count is D%2BN.
Each dime is worth 10 and each nickel is worth 5.
Total value equation:
10D%2B5N=95
1.2D%2BN=19
.
.
Total coin count equation:
D%2BN=1%2B2D
2.N=1%2BD
Substitute eq. 2 into eq. 1,
2D%2B%281%2BD%29=19
3D=18
highlight%28D=6%29
Then from eq. 2,
N=1%2B6
highlight%28N=7%29

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi, 

Let x represent the number of dimes.  

question statets the total coins then is (2x + 1) 

The number of nickels is total coins - the number of dimes = [(2x+1) - x ]

Note: there are 5 cents in a nickel and 10 cents in a dime.

5[(2x+1) - x ] + 10x = 95 cents

simplify and slove for x

5[x + 1] + 10x = 95

5x + 5 + 10x = 95

15x = 90

x = 6, the number of dimes

number of nickles is [(2*6 + 1) - 6] = 7 nickels



checking our answer

5*7 + 6*10 = 35 cents + 60 cents = 95 cents