SOLUTION: suppose M is between L and N use segment Additing postulate to solve for the variable then find lengths of line LM, line MN and line LN.
LM= 3x+8
MN= 2x-5
LN= 23
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Question 261876: suppose M is between L and N use segment Additing postulate to solve for the variable then find lengths of line LM, line MN and line LN.
LM= 3x+8
MN= 2x-5
LN= 23
Found 3 solutions by drk, solver91311, checkley77:
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
M is between L and N.
LM + MN = LN by segment addition postulate.
So,
combine like terms to get
subtract 3 to get
divide by 5 to get
LM = 20
MN = 3
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The segment addition principle says that if a segment is divided into a number of smaller segments then I can add the measures of all of the small segments to get the measure of the original segment. In other words:
Substituting the given values we get:
\ +\ \left(2x\,-\,5\right)\ =\ 23)
Solve the equation for 
.
John
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
LM= 3x+8
MN= 2x-5
LN= 23
3x+8+2x-5=23
5x=23-8+5
5x=20
x=20/5
x=4
LM=3*4+8=12+8=20
MN=2*4-5=8-5=3
PROOF:
20+3=23
23=23
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