Question 208971: Given that 29a031 x 342 = 100900b02 where a and b denote two missing interger, find the value of a+b
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! a=5,,,,b=6,,,,,a+b= 11
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check,,,295031 * 342 = 100900602
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work
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.,,,,,,,,,,,,29a031__
,,,,,342[ 100900b02
,,,,,,,,,,,684
,,,,,,,,,,,___
,,,,,,,,,,,3250
,,,,,,,,,,,3078
,,,,,,,,,,,____
,,,,,,,,,,,,1720,,,,,,,1720/342=5.03,,,,therefore a=5,,,,,5*342=1710
,,,,,,,,,,,,1710
,,,,,,,,,,,,____
,,,,,,,,,,,,,,,10b
,,,,,,,,,,,,,,,,,0
,,,,,,,,,,,,,,,___
,,,,,,,,,,,,,,,10b0
,,,,,,,,,,,,,,,1026
,,,,,,,,,,,,,,,_____
,,,,,,,,,,,,,,,(b-1-2) 42
,,,,,,,,,,,,,,,,,,,,342
,,,,,,,,,,,,,,,,,________
,,,,,,,,,,,,,,,,,,,,,0
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therefore b-1-2 =3,,,,,or b= 6
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