SOLUTION: solve systems of equations by graphing 1. y = 2x -4 y = -3x+1 2. 3x - 7y = -6 x + 2y = 11 3. 2x +3y = 7 2x - 3y = y 4. 1/4x + 2y = 5 2x - y = 6

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: solve systems of equations by graphing 1. y = 2x -4 y = -3x+1 2. 3x - 7y = -6 x + 2y = 11 3. 2x +3y = 7 2x - 3y = y 4. 1/4x + 2y = 5 2x - y = 6       Log On


   

Question 201154: solve systems of equations by graphing
1. y = 2x -4
y = -3x+1
2. 3x - 7y = -6
x + 2y = 11
3. 2x +3y = 7
2x - 3y = y
4. 1/4x + 2y = 5
2x - y = 6
5. 1/2x - y = 0
1/4x +1/2y = -2
Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!


We'll do #1 and you can take care of the rest. It's all the same sequence anyway.

1)Givensystem%28y+=+2x+-4%28red%28EQN1%29%29%2Cy+=+-3x%2B1%28red%28EQN2%29%29%29

red%28EQN1%29, Let Fy=0
0=2x-4
4=2x ---> cross%284%292%2Fcross%282%29=cross%282%29x%2Fcross%282%29}
red%28x=2%29, X-Intercept
Let Fx=0:
y=2%280%29-4
red%28y=-4%29, Y-Intercept


red%28EQN2%29, Let Fy=0
0=-3x%2B1
3x=1 ---> cross%283%29x%2Fcross%283%29=1%2F3
red%28x=1%2F3%29, X-Intercept
Let Fx=0:
y=-3%280%29%2B1
red%28y=1%29, Y-Intercept


Seeing the two lines, red%28EQN1%29 & red%28EQN2%29:
----> Point of interection (1,-2)
*Note: we can calculate the point of Intersection by equating the two eqns.
red%28EQN1%29=red%28EQN2%29
2x-4=-3x=1
2x%2B3x=4%2B1
5x=5 ---->cross%285%29x%2Fcross%285%29=cross%285%291%2Fcross%285%291
red%28x=1%29, substitute in either eqn. (we use red%28EQN1%29)
y=2%28highlight%281%29%29-4=2-4
red%28y=-2%29
*Point of Intersection, (1,-2)

Thank you,
Jojo