SOLUTION: {{{system(-10x - 11y + 7z = 145, 7x - 4y - 3z = 53, -5x - y = 146)}}} I need to solve this using any method. Id like to see the steps and the correct answer. I thi

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: {{{system(-10x - 11y + 7z = 145, 7x - 4y - 3z = 53, -5x - y = 146)}}} I need to solve this using any method. Id like to see the steps and the correct answer. I thi      Log On


   



Question 160537:
I need to solve this using any method. Id like to see the steps and the correct
answer. I think maybe I should start by multiplying the 3rd equation by 2 and
then subtract it from the 1st equation? I'm trying to make sense of this but I
just cant figure it out. I really appreciate your time. Thank you.

Found 2 solutions by vleith, Edwin McCravy:
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
If you know matrices, you can use that. But I suspect you are not there yet.
So, you might try substitution.
I would start with equation 3. Use it to find y in terms of x
-5x+-+y+=+146+
-y+=+5x+%2B+146
+y+=+146-5x
You can then substitute that value for y into both equations 1 and 2.
-10x+-+11y+%2B+7z+=+145
-10x+-+11%28146-5x%29+%2B+7z+=+145
Simplify this to get an equation with just x and z in it
Use it to find x in terms of z
7x+-+4y+-+3z+=+53
7x+-+4%28146-5x%29+-+3z+=+53
Simplify this one too and get an equation with just x and z.
Substitute the z value in this last equation with the "z in terms of x" from the earlier equation.
You now have one equation with only x and constants in it.
Solve for x.
Niw use this value of x and the equation with z in terms of x to find z.
Then use x and z in any of the equations to solve for y (I would use the third original equation since it has only x and y in it)

Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
Edwin's solution:


That would work, but it would be the best way.

First you should observe that z is already eliminated
from the third equation, so you should eliminate z 
from the first two equations:

To eliminate z from the first two equations:

Multiply the first equation by 3 and the second equation 
by 7, then add them:

3[-10x - 11y + 7z = 145]
7[  7x -  4y - 3z =  53]

  -30x - 33y + 21z = 435
   49x - 28y - 21z = 371
   19x - 61y       = 806

Now we take the third original equation with
this equation and solve this system:

system%28-5x-y=+146%2C+19x+-+61y+++++++=+806%29

We can do this by substitution:

Solve the first equation for y:

matrix%283%2C1%2C-5x-y=146%2C-y=146%2B5x%2Cy=-146-5x%29

Substitute -146-5x for y in

19x-61y=806
19x-61%28-146-5x%29=806
19x%2B8906%2B305x=806
324x%2B8906=806
324x=-8100
x=-25

Substitute that into y=-146-5x
y=-146-5x
y=-146-5%28-25%29
y=-146%2B125%29
y=-21

Now substitute x=-25 and y=-21 into
either one of the first two original equations.

7x+-++4y+-+3z+=++53
7%28-25%29+-++4%28-21%29+-+3z+=++53
-175+%2B84+-+3z+=++53
-91-3z=53
-3z=144
z=-48

Edwin