SOLUTION: 6x+3y=-2 9y+10x=-2 I have to solve this problem using elimination and I don't understand this at all could someone please help me!

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: 6x+3y=-2 9y+10x=-2 I have to solve this problem using elimination and I don't understand this at all could someone please help me!      Log On


   



Question 120128: 6x+3y=-2
9y+10x=-2
I have to solve this problem using elimination and I don't understand this at all could someone please help me!

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition


Lets start with the given system of linear equations

6%2Ax%2B3%2Ay=-2
10%2Ax%2B9%2Ay=-2

In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).

So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.

So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 6 and 10 to some equal number, we could try to get them to the LCM.

Since the LCM of 6 and 10 is 30, we need to multiply both sides of the top equation by 5 and multiply both sides of the bottom equation by -3 like this:

5%2A%286%2Ax%2B3%2Ay%29=%28-2%29%2A5 Multiply the top equation (both sides) by 5
-3%2A%2810%2Ax%2B9%2Ay%29=%28-2%29%2A-3 Multiply the bottom equation (both sides) by -3


So after multiplying we get this:
30%2Ax%2B15%2Ay=-10
-30%2Ax-27%2Ay=6

Notice how 30 and -30 add to zero (ie 30%2B-30=0)


Now add the equations together. In order to add 2 equations, group like terms and combine them
%2830%2Ax-30%2Ax%29%2B%2815%2Ay-27%2Ay%29=-10%2B6

%2830-30%29%2Ax%2B%2815-27%29y=-10%2B6

cross%2830%2B-30%29%2Ax%2B%2815-27%29%2Ay=-10%2B6 Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.



So after adding and canceling out the x terms we're left with:

-12%2Ay=-4

y=-4%2F-12 Divide both sides by -12 to solve for y



y=1%2F3 Reduce


Now plug this answer into the top equation 6%2Ax%2B3%2Ay=-2 to solve for x

6%2Ax%2B3%281%2F3%29=-2 Plug in y=1%2F3


6%2Ax%2B3%2F3=-2 Multiply



6%2Ax%2B1=-2 Reduce



6%2Ax=-2-1 Subtract 1 from both sides

6%2Ax=-3 Combine the terms on the right side

cross%28%281%2F6%29%286%29%29%2Ax=%28-3%29%281%2F6%29 Multiply both sides by 1%2F6. This will cancel out 6 on the left side.


x=-1%2F2 Multiply the terms on the right side


So our answer is

x=-1%2F2, y=1%2F3

which also looks like

(-1%2F2, 1%2F3)

Notice if we graph the equations (if you need help with graphing, check out this solver)

6%2Ax%2B3%2Ay=-2
10%2Ax%2B9%2Ay=-2

we get



graph of 6%2Ax%2B3%2Ay=-2 (red) 10%2Ax%2B9%2Ay=-2 (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).


and we can see that the two equations intersect at (-1%2F2,1%2F3). This verifies our answer.