SOLUTION: Use two equations in two variables to solve the application.
A merchant wants to mix peanuts worth $3 per pound with jelly beans worth $1.50 per pound to make 30 pounds of a mi
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-> SOLUTION: Use two equations in two variables to solve the application.
A merchant wants to mix peanuts worth $3 per pound with jelly beans worth $1.50 per pound to make 30 pounds of a mi
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Question 1130791: Use two equations in two variables to solve the application.
A merchant wants to mix peanuts worth $3 per pound with jelly beans worth $1.50 per pound to make 30 pounds of a mixture worth $2.10 per pound. How many pounds of each should he use? (find # of lbs used for peanuts and jelly beans). Found 2 solutions by Alan3354, josgarithmetic:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! A merchant wants to mix peanuts worth $3 per pound with jelly beans worth $1.50 per pound to make 30 pounds of a mixture worth $2.10 per pound. How many pounds of each should he use? (find # of lbs used for peanuts and jelly beans).
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p + j = 30 --- total mix
3p + 1.5j = 2.1*30 --- total cost
etc.
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