SOLUTION: Two trains leave towns 692 mi apart at the same time and travel toward each other. One train travels
21/mi/h slower than the other. If they meet in 4 hours, what is the rate of e
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-> SOLUTION: Two trains leave towns 692 mi apart at the same time and travel toward each other. One train travels
21/mi/h slower than the other. If they meet in 4 hours, what is the rate of e
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Question 1112890: Two trains leave towns 692 mi apart at the same time and travel toward each other. One train travels
21/mi/h slower than the other. If they meet in 4 hours, what is the rate of each train? Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let = the speed of the faster car in mi/hr = the speed of the slower car
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You can think of this as one of the cars travelling
at the sum of their speeds and the other one
standing still
and
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The faster train's rate is 97 mi/hr
The slower train's rate is 76 mi/hr
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check: mi
and
and
OK
