SOLUTION: Mark has a total of 41 coins consisting of nickels and quarters the total value of the coins is 4.85. How many of each type of coin does he have?

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: Mark has a total of 41 coins consisting of nickels and quarters the total value of the coins is 4.85. How many of each type of coin does he have?       Log On


   

Question 1100989: Mark has a total of 41 coins consisting of nickels and quarters the total value of the coins is 4.85. How many of each type of coin does he have?
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
system%28n%2Bq=41%2C5n%2B25q=485%29

system%28n%2Bq=41%2Cn%2B5q=97%29
Solve for n and q.


Good next step should lead to 4q=97-41.

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


...or solve the problem informally, like this:

If all 41 coins were nickels, the value would be 41*$.05 = $2.05.

The actual value is $4.85, which is $2.80 more than $2.05.

Each quarter is worth $.20 more than each nickel.

So the number of quarters is 2.80%2F.20+=+14

And then the number of nickels is 41-14 = 27