Lesson Geometric interpretation of a linear system of two equations in two unknowns
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<H2>Geometric interpretation of a linear system of two equations in two unknowns</H2> Geometric interpretation of a linear system of two equations in two unknowns is the geometric presentation of the two straight lines that correspond to linear functions of these equations. It gives you a visual image showing immediately if the given linear system is consistent or inconsistent; whether the equations are dependent or not. Below are some examples. Note that the systems of equations in these examples were just considered from the point of view of their solutions in the lessons - <A HREF= http://www.algebra.com/algebra/homework/coordinate/lessons/Solution-of-the-lin-system-of-two-eqns-by-the-Subst-method.lesson> Solution of the linear system of two equations with two unknowns by the Substitution method</A> and - <A HREF= http://www.algebra.com/algebra/homework/coordinate/lessons/Solution-of-the-lin-syst-of-two-eqns-with-two-unknowns-Elimination-method.lesson> Solution of the linear system of two equations with two unknowns by the Elimination method</A> in this module. This lesson is focused on the geometric interpretation, and its goal is to extend your ability to analyze such systems of equations. <TABLE cellspacing="10"> <TR> <TD> <H3>Example 1</H3> Let us consider a system of equations {{{system (2x + y = 5, -4x + 6y = -2 )}}} <B>Figure 1</B> to the right shows two straight lines {{{2x+y=5}}} (in black) and {{{-4x+6y=-2}}} (in blue). These straight lines intersect at the point <B>(x,y) = (2,1)</B>. Note that this intersection point is exactly the solution of the system (see the lessons referred above). The fact that these straight lines intersect and have only one common point corresponds to that the system of equations is <B>consistent</B> and the equations are <B>independent</B>. </TD> <TD> {{{drawing( 200, 200, -2, 4, -2, 4, grid(1), line (-2, 9, 4, -3), locate ( 2.2,-0.6, 2x+y=5), blue(line (-2, -1.666, 4, 2.333)), locate (1.9, 2.7, -4x+6y=-2) )}}} <B>Figure 1. Geometric presentation</B> <B>to Example 1</B> </TD> </TR> </TABLE> <TABLE cellspacing="10"> <TR> <TD> <H3>Example 2</H3> Let us consider a system of equations {{{system (3x - 2y = 5, 5x - y = 6 )}}} <B>Figure 2</B> to the right shows two straight lines {{{3x-2y=5}}} (in black) and {{{5x-y=6}}} (in blue). These straight lines intersect, and the intersection point is <B>(x,y) = (1,-1)</B>. It is exactly the solution of the system (see the lessons referred above). The fact that these straight lines intersect and have only one common point corresponds to that the system of equations is <B>consistent</B> and the equations are <B>independent</B>. </TD> <TD> {{{drawing( 200, 200, -2, 4, -3, 3, grid(1), line (-2, -5.5, 4, 3.5), locate ( 2.2, 0.9, 3x-2y=5), blue(line (-2, -16, 4, 14)), locate (0.9, 2.7, 5x-y=6) )}}} <B>Figure 2. Geometric presentation</B> <B>to Example 2</B> </TD> </TR> </TABLE> <TABLE cellspacing="10"> <TR> <TD> <H3>Example 3</H3> Let us consider a system of equations {{{system (3x - 2y = 5, 12x - 8y = 20 )}}} <B>Figure 3</B> to the right shows two straight lines {{{3x-2y=5}}} (in black) and {{{12x-8y=20}}} (in blue). These straight lines actually coincide, so all their points are common and all represent solutions of the equation system (see the lessons referred above). The fact that these straight lines coincide and have all points common corresponds to that the system of equations is <B>consistent</B> and the equations are <B>dependent</B>. </TD> <TD> {{{drawing( 200, 200, -2, 4, -3, 3, grid(1), line (-2, -5.5, 4, 3.5), locate ( 1.5, 0.9, 3x-2y=5), blue(line (-2, -5.5, 4, 3.5)), locate (1.4, 2.7, 12x-8y=20) )}}} <B>Figure 3. Geometric presentation</B> <B>to Example 3</B> </TD> </TR> </TABLE> <TABLE cellspacing="10"> <TR> <TD> <H3>Example 4</H3> Let us consider a system of equations {{{system (3x - 2y = 5, 12x - 8y = 15 )}}} <B>Figure 4</B> to the right shows two straight lines {{{3x-2y=5}}} (in black) and {{{12x-8y=15}}} (in blue). These straight lines are actually parallel, so the lines have no common points (see the lessons referred above). The fact that these straight lines are parallel and have no common points corresponds to that the system of equations is <B>inconsistent</B> and the equations are <B>dependent</B>. </TD> <TD> {{{drawing( 200, 200, -2, 4, -3, 3, grid(1), line (-2, -5.5, 4, 3.5), locate ( 2.1, 0.7, 3x-2y=5), blue(line (-2, -4.875, 4, 4.125)), locate (0.4, 2.7, 12x-8y=15) )}}} <B>Figure 4. Geometric presentation</B> <B>to Example 4</B> </TD> </TR> </TABLE> The Table below lists, in the ordered form, properties of a linear system of two equations in two unknowns along with the corresponding properties of their geometric presentations. Equivalent properties are listed in the row cells of the Table, from the left to the right, while the different properties are listed in the column cells, from the top to the bottom. <TABLE cellspacing="10"> <TR> <TD> </TD> <TD> <B>The solution existence and multiplicity</B> </TD> <TD> <B>Terminology</B> </TD> <TD> <B>The coefficient properties</B> </TD> <TD> <B>Geometric presentation</B> </TD> </TR> </TABLE> <TABLE cellspacing="10"> <TR> <TD> 1. </TD> <TD> The system of equations has a solution, and the existing solution is unique. </TD> <TD> The system of equations is <B>consistent</B>, and equations are <B>independent</B>. </TD> <TD> The row of coefficients of the first equation is not proportional to that of the second equation. </TD> <TD> In the geometric presentation two straight lines intersect and have only one common point. </TD> </TR> </TABLE> <TABLE cellspacing="10"> <TR> <TD> 2. </TD> <TD> The system of equations has more than one solution. (==) The system of equations has infinitely many solutions. </TD> <TD> The system of equations is <B>consistent</B>, and equations are <B>dependent</B>. </TD> <TD> The row of coefficients and the right side of the first equation is proportional to that of the second equation. </TD> <TD> In the geometric presentation two straight lines coincide and have all points common. </TD> </TR> </TABLE> <TABLE cellspacing="10"> <TR> <TD> 3. </TD> <TD> The system of equations has no solutions. </TD> <TD> The system of equations is <B>inconsistent</B>, and equations are <B>dependent</B>. </TD> <TD> The row of coefficients of the first equation is proportional to that of the second equation, but the right sides are not proportional in this way. </TD> <TD> In the geometric presentation two straight lines are parallel and have no common points. </TD> </TR> </TABLE> My other lessons on solution of the linear system of two equations in two unknowns in this site are - <A HREF = http://www.algebra.com/algebra/homework/coordinate/lessons/Solution-of-the-lin-system-of-two-eqns-by-the-Subst-method.lesson>Solution of a linear system of two equations in two unknowns by the Substitution method</A> - <A HREF = http://www.algebra.com/algebra/homework/coordinate/lessons/Solution-of-the-lin-syst-of-two-eqns-with-two-unknowns-Elimination-method.lesson>Solution of a linear system of two equations in two unknowns by the Elimination method</A> - <A HREF =http://www.algebra.com/algebra/homework/coordinate/lessons/Solution-of-the-lin-syst-of-two-eqns-with-two-unknowns-using-det.lesson>Solution of a linear system of two equations in two unknowns using determinant</A> - <A HREF=https://www.algebra.com/algebra/homework/coordinate/lessons/Useful-tricks-when-solving-systems-of-2-eqns-in-2-unknowns-by-the-Subst-method.lesson>Useful tricks when solving systems of 2 equations in 2 unknowns by the Substitution method</A> - <A HREF =http://www.algebra.com/algebra/homework/coordinate/lessons/Solving-word-probs-using-linear-systems-of-two-eqns-with-two-unknowns.lesson>Solving word problems using linear systems of two equations in two unknowns</A> - <A HREF=https://www.algebra.com/algebra/homework/coordinate/lessons/Word-problems-that-lead-to-a-simple-system-of-two-equations-in--wo-unknowns.lesson>Word problems that lead to a simple system of two equations in two unknowns</A> - 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