SOLUTION: Graph 3x+y <5

Algebra ->  Conversion and Units of Measurement -> SOLUTION: Graph 3x+y <5      Log On


   



Question 865120: Graph 3x+y <5
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
To graph 3x%2By+%3C+5 we first need to graph 3x%2By=5


3x%2By=5


y=5-3x


y=-3x%2B5


This line has a slope of -3 and a y-intercept of 5. This is the point (0,5). Another point on this line is (1,2). You would start at (0,5) and go down 3 and over to the right 1 to get to (1,2)


So plot (0,5) and (1,2). Draw a dashed line through these two points. This is the boundary of the shaded region and the dashed line means we are NOT including the boundary line in the solution set.


If you were to solve 3x%2By+%3C+5 for y, you'd get y+%3C+-3x%2B5 and you follow the same basic steps as shown above.


Since the inequality sign is a less than sign, we shade below the dashed line.


To summarize, we have a dashed line and we are shading below the dashed line. This dashed line goes through (0,5) and (1,2)