SOLUTION: If 5 apples and 4 oranges cost $3.40 while 7 apples and 6 oranges cost $4.90.Find the cost of an apple and an orange.

Algebra ->  Conversion and Units of Measurement -> SOLUTION: If 5 apples and 4 oranges cost $3.40 while 7 apples and 6 oranges cost $4.90.Find the cost of an apple and an orange.      Log On


   



Question 7618: If 5 apples and 4 oranges cost $3.40 while 7 apples and 6 oranges cost $4.90.Find the cost of an apple and an orange.
Answer by prabhjyot(165) About Me  (Show Source):
You can put this solution on YOUR website!
In the problem we have to find price of one apple and one orange
Let cost of apple be x and cost of orange be y
Now given 5 apples and 4 oranges cost $3.40
so we get
5x +4y=3.4 ------>(1)
7 apples and 6 oranges cost $4.90
7x + 6y=4.9 ---->(2)
Now we have two linear equation,we solve these equations using substituion method
from equation (1) we get
x+=+%283.4+-4y%29%2F5 --->(3)
Substituting the above equation (3)into the second equation:
7%283.4%2B4y%29%2F5%2B6y+=+4.9
y = 0.35
Now, put y = 0.35 into equation(3)
x+=+%283.4-4%280.35%29%29%2F5+=+0.4
So x=0.4
y=0.35
So cost of one apple = x= $0.4
and cost of one orange = y=$ 0.35