SOLUTION: How would i go about factoring completely with having a GCF: 16a^6b^6+4ab^4-8ab^7

Algebra ->  Conversion and Units of Measurement -> SOLUTION: How would i go about factoring completely with having a GCF: 16a^6b^6+4ab^4-8ab^7       Log On


   

Question 569032: How would i go about factoring completely with having a GCF: 16a^6b^6+4ab^4-8ab^7
Found 3 solutions by CubeyThePenguin, MathTherapy, greenestamps:
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
GCF(16a^6b^6, 4ab^2, 8ab^7) = 4ab^2

16a%5E6b%5E6+%2B++4ab%5E2-+8ab%5E7+=+4ab%5E2%284a%5E5%2A+b%5E4+%2B+1+-+2b%5E5%29

(The terms inside the parentheses have no common factors.)

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

How would i go about factoring completely with having a GCF: 16a^6b^6+4ab^4-8ab^7
That's WRONG!! It's NOT 16a%5E6b%5E6+%2B++4ab%5E2-+8ab%5E7+=+4ab%5E2%284a%5E5%2A+b%5E4+%2B+1+-+2b%5E5%29, so: cross%2816a%5E6b%5E6+%2B++4ab%5E2-+8ab%5E7+=+4ab%5E2%284a%5E5%2A+b%5E4+%2B+1+-+2b%5E5%29%29

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


The careless response from tutor @CoreyThePenguin is not correct, as it does not use the correct original expression.

16a%5E6b%5E6
4ab%5E4
-8ab%5E7

The coefficients 16, 4, and -8 have a GCF of 4.
The "a" factors are a^6, a, and a; their GCF is a.
The "b" factors are b^6, b^4, and b^7; their GCF is b^4.

The GCF of the given terms is 4ab%5E4.

ANSWER: 16a%5E6b%5E6%2B4ab%5E4-8ab%5E7+=+4ab%5E4%284a%5E5b%5E2%2B1-2b%5E3%29