SOLUTION: Lloyd gave 1/2 his marbles to Lee. Then, he gave 2/3 of the remaining ones to Lynn. If he ended up with ten marbles, how many did he have when started?

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Question 1202349: Lloyd gave 1/2 his marbles to Lee. Then, he gave 2/3 of the remaining ones to Lynn. If he ended up with ten marbles, how many did he have when started?
Found 2 solutions by mananth, josgarithmetic:
Answer by mananth(16946) About Me  (Show Source):
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Lloyd gave 1/2 his marbles to Lee. Then, he gave 2/3 of the remaining ones to Lynn. If he ended up with ten marbles, how many did he have when started?
Let him have x marbles initially
gave 1/2 his marbles to Lee
x/2
remaining with him
x-x/2= x/2
2/3 of the remaining ones to Lynn
2/3(x/2)= x/3
x-x/2-x/3 = 10
simplify
Multiply by LCM 6
6x-3x-2x=60
x=60 Llyod had 60 marbles initially

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
n number of marbles to start

(1)
n%2F2 remaining

(2)
%281%2F3%29%281%2F2%29n remaining

(3)
He has now 10 marbles.
n%2F6=10

highlight%28n=60%29