SOLUTION: A 3.0kg cinder block is dragged down a (horizontal)pinic table. If the coefficient of kinetic friction is 0.8 what is the friction force on the block

Algebra ->  Conversion and Units of Measurement -> SOLUTION: A 3.0kg cinder block is dragged down a (horizontal)pinic table. If the coefficient of kinetic friction is 0.8 what is the friction force on the block      Log On


   

Question 1182096: A 3.0kg cinder block is dragged down a (horizontal)pinic table. If the coefficient of kinetic friction is 0.8 what is the friction force on the block
Answer by ikleyn(52786) About Me  (Show Source):
You can put this solution on YOUR website!
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The friction force is the product of the weight   3.0 kg * 10 m/s^2 = 30  Newtons by the kinetic friction coefficient of  0.8.

So,  your answer is   30*0.8 = 24 N.