Question 1138449: Find the product in the base indicated.
37 (base 8) * 21 (base 8)
Answer by greenestamps(13200)   (Show Source):
You can put this solution on YOUR website!
(1) 37*1 in base 8 (or in ANY base) is 37.
(2) 37*2 in base 8 is 76:
7*2=14 (base 10) = 16 (base 8) so the last digit is 6; carry the 1
3*2=6, plus the carry of 1 makes 7
So 37*2 in base 8 is 76.
Then 37 (base 8) times 21 (base 8) is, in base 8,
37
* 21
----
37
76
----
1017
The last digit in the product is 7.
The next digit is 3+6 which is 9 in base 10 but 11 in base 8; this digit is 1 and carry the other 1.
Then 7 plus the carry of 1 makes 8, which is 10 in base 8; since there are no more columns to add, write the 10 as the first two digits.
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