SOLUTION: Please help me solve this problem with solutions so i can understand clearly: {{{(7-5i)/(3+6i)}}}

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Question 776314: Please help me solve this problem with solutions so i can understand clearly: %287-5i%29%2F%283%2B6i%29
Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
(7-5i)/(3+6i)
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Multiply numerator and denominator by (3-6i) to get:
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= [(7-5i)(3-6i)]/[3^2+6^2]
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= [21-42i-15i-30]/45
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= (-9-57i)/45
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Cheers,
Stan H.
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Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+%287-5i%29%2F%283%2B6i%29+
What you are trying to do is to get this
into the form +a+%2B+b%2Ai+
------------------------
Multiply both top and bottom by +3+-+6i+
This is called the complex conjugate
+%28+%287-5i%29%2F%283%2B6i%29+%29%2A+%28+%28+3+-+6i+%29+%2F+%28+3+-+6i+%29+%29+
This is the same as multiplying by +1+,
so you haven't changed anything
----------------------------
Rewrite it as:
+%28+%28+7+-+5i+%29%2A%28+3+-+6i+%29+%29+%2F+%28+%28+3+%2B+6i+%29%2A%28+3+-+6i+%29+%29+
Now multiply out the denominator as follows:
+%28+3+%2B+6i+%29%2A%28+3+-+6i+%29+=+9+%2B+18i+-+18i+-+36i%5E2+
Using the fact that +i%5E2+=+-1+, I get:
+%28+3+%2B+6i+%29%2A%28+3+-+6i+%29+=+9+-+36%2A%28-1%29+
+%28+3+%2B+6i+%29%2A%28+3+-+6i+%29+=+9+%2B+36+
+%28+3+%2B+6i+%29%2A%28+3+-+6i+%29+=+45+
-------------------------
Now my expression is:
+%28+%28+7+-+5i+%29%2A%28+3+-+6i+%29+%29+%2F+45+
Now multiply out the numerator:
+21+-+15i+-+42i+%2B+30i%5E2+
+21+-+57i+-+30+
+-9+-+57i+
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Putting the numerator and denominator
together, I get:
+%28+-9+-+57i+%29+%2F+45+, or
+-9%2F45+-+%2857%2F45%29%2Ai+
+-1%2F5+-+%2857%2F45%29%2Ai+
-------------------
I can check this result:
+%287-5i%29%2F%283%2B6i%29+=+%28+-9+-+57i+%29+%2F+45
Multiply both sides by +%28+3+%2B+6i+%29%2A45+
+%28+7+-+5i+%29%2A45+=+%28+-9+-+57i+%29%2A%28+3+%2B+6i+%29+
+315+-+225i+=+-27+-+171i+-+54i+-+342i%5E2+
+315+-+225i+=+-27+-+171i+-+54i+%2B+342+
+315+-+225i+=+315+-+225i++
OK