SOLUTION: Find the values of x and y, where x and y are real numbers. 6 + (9x + y)i = 3x − 2i I'm really bad at these. Thanks for your help!

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson  -> Lesson -> SOLUTION: Find the values of x and y, where x and y are real numbers. 6 + (9x + y)i = 3x − 2i I'm really bad at these. Thanks for your help!      Log On


   

Question 709483: Find the values of x and y, where x and y are real numbers.
6 + (9x + y)i = 3x − 2i

I'm really bad at these. Thanks for your help!
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
Just treat i as any other number. Finish by collecting and simplifying terms of y.


6 + (9x + y)i = 3x − 2i
6+9xi+yi=3x-2i
6+9xi+yi-3x+2i=0
6+6xi+yi+2i=0
6+(6x+y+2)i=0
highlight%286%2B%282%2B6x%2By%29i=0%29, This is IT, unless you really wanted y in terms of x, or x in terms of y.