SOLUTION: 3\4+i

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson  -> Lesson -> SOLUTION: 3\4+i      Log On


   

Question 701492: 3\4+i
Found 2 solutions by stanbon, MathLover1:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
3\(4+i)
-----
Multiply numerator and denominator by 4-i to get:
= (3(4-i))/(16+1)
---
= (12-3i)/17
===============
Cheers,
Stan H.
===============

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

if you have this 3%2F4%2Bi than you have complex number and only what you can do is write real part as decimal number 0.75%2Bi
but, if you have this 3%2F%284%2Bi%29 than you multiply both nominator and denominator by %284-i%29 to eliminate i from denominator

3%2F%284%2Bi%29

3%284-i%29%2F%28%284-i%29%284%2Bi%29%29

%2812-3i%29%2F%284%5E2-i%5E2%29

%2812-3i%29%2F%2816-%28-1%29%29

%2812-3i%29%2F%2816%2B1%29

%2812-3i%29%2F17

12%2F17-3i%2F17

0.706-0.1771i