SOLUTION: 2-3i/1+i

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Question 697390: 2-3i/1+i
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
I bet you meant (2-3i)/(1+i) = %282-3i%29%2F%281%2Bi%29
1-i is the conjugate of 1%2Bi
When you multiply conjugate complex numbers, you get a real number.
%281%2Bi%29%281-i%29=1%5E2-i%5E2=1-%28-1%29-2
That is very useful when trying to get rid of complex denominators.
You just multiply numerator and denominator times the conjugate of the denominator:


NOTE:
2-3i/1+i = 2-3i%2F1%2Bi=2-3i%2Bi=2-2i is a different (easier) problem.
If want to write %282-3i%29%2F%281%2Bi%29 ,
and you are not able to draw a long horizontal line with 2-3i above it and 1%2Bi below it,
you must write out the brackets around 2-3i and around 1%2Bi that the long horizontal fraction bar implies.