SOLUTION: Solve. Write all apparent solutions. Cross out those that are extraneous THE SQUARE ROOT OF u-3 - THE SQUARE ROOT OF u =3 [the square root of u-3 (minus) the square root of u (

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson  -> Lesson -> SOLUTION: Solve. Write all apparent solutions. Cross out those that are extraneous THE SQUARE ROOT OF u-3 - THE SQUARE ROOT OF u =3 [the square root of u-3 (minus) the square root of u (      Log On


   

Question 63024This question is from textbook Intermediate Algebra
: Solve. Write all apparent solutions. Cross out those that are extraneous
THE SQUARE ROOT OF u-3 - THE SQUARE ROOT OF u =3
[the square root of u-3 (minus) the square root of u (equals) 3] This question is from textbook Intermediate Algebra

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
Solve. Write all apparent solutions. Cross out those that are extraneous
sqrt%28u-3%29-sqrt%28u%29=3
sqrt%28u-3%29-sqrt%28u%29%2Bsqrt%28u%29=sqrt%28u%29%2B3
sqrt%28u-3%29=sqrt%28u%29%2B3
%28sqrt%28u-3%29%29%5E2=%28sqrt%28u%29%2B3%29%5E2
u-3=%28sqrt%28u%29%2B3%29%28sqrt%28u%29%2B3%29
u-3=sqrt%28u%29%28sqrt%28u%29%2B3%29%2B3%28sqrt%28u%29%2B3%29
u-3=sqrt%28u%5E2%29%2B3sqrt%28u%29%2B3sqrt%28u%29%2B9
u-3=u%2B6sqrt%28u%29%2B9
u-u-3-9=u-u%2B6sqrt%28u%29%2B9-9
-12=6sqrt%28u%29
-12%2F6=6sqrt%28u%29%2F6
-2=sqrt%28u%29
%28-2%29%5E2=%28sqrt%28u%29%29%5E2
4=u Check to see if it's extraneous.
sqrt%284-3%29-sqrt%284%29=3
sqrt%281%29-2=3
1-2=3
-1=3 This is not true, u=4 is extraneous, there is no soltuion.
Happy Calculating!!!