SOLUTION: I have to find all real and imaginary numbers. My guess is to factor, but I don't think it does. 3x(x)+ 2x + 1 = 0

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson  -> Lesson -> SOLUTION: I have to find all real and imaginary numbers. My guess is to factor, but I don't think it does. 3x(x)+ 2x + 1 = 0       Log On


   

Question 6274: I have to find all real and imaginary numbers. My guess is to factor, but I don't think it does.
3x(x)+ 2x + 1 = 0
Answer by xcentaur(357) About Me  (Show Source):
You can put this solution on YOUR website!
3x^2 + 2x + 1 = 0


x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x=[-2 +- sqrt(4 - 4(3)(1))]/2(3)
x=[-2 +- sqrt(4 - 4(3)(1))]/2(3)
x=[-2 +- sqrt(4 - 12)]/6
x=[-2 +- sqrt(-8)]/6


Now the discriminant is less than zero (-8). Therefore there are no real solutions,both will be imaginary.


square root of -8 = +- 2.8284271247461900976033774484194


x=[-2 +- i(2.8284271247461900976033774484194)]/6


Hope this helps,
good luck