SOLUTION: it says perform the indicated operation, and write the result in the standard form a+bi. the equation is 2+3i/1-5i. i have no clue what to do

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson  -> Lesson -> SOLUTION: it says perform the indicated operation, and write the result in the standard form a+bi. the equation is 2+3i/1-5i. i have no clue what to do       Log On


   

Question 386622: it says perform the indicated operation, and write the result in the standard form a+bi. the equation is 2+3i/1-5i. i have no clue what to do


Answer by ptaylor(2198) About Me  (Show Source):
You can put this solution on YOUR website!
OK
(2+3i)/(1-5i)
We first multiply both the numerator and the denominator by the conjugate of (1-5i) which is (1+5i) and this will get rid of the complex number in the denominator.
((2+3i)(1+5i))/((1-5i)(1+5i)) when we carry out the multiplications, we get:
(2+10i+3i+15i^2)/(1-25i^2) now we know that i^2=-1, so:
(-13+13i)/26 or
13(-1+i)/26=(-1+i)/2
Hope this helps---ptaylor