SOLUTION: On a farm there are 3 legged cow and 2 legged chickens. There are 81 heads and 209 legs. How many of each are there? I am trying to recall how to solve this problem. Thank you

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson  -> Lesson -> SOLUTION: On a farm there are 3 legged cow and 2 legged chickens. There are 81 heads and 209 legs. How many of each are there? I am trying to recall how to solve this problem. Thank you      Log On


   

Question 277764: On a farm there are 3 legged cow and 2 legged chickens. There are 81 heads and 209 legs. How many of each are there?
I am trying to recall how to solve this problem. Thank you for your help.
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
w+c=81
3w+2c=209
chicken=34 cow=47