Question 255196: 7+3i/3+9i
Answer by dabanfield(803)   (Show Source):
You can put this solution on YOUR website! 7+3i/3+9i
Multiply numerator by the complex conjugate of 3+9i.
The complex conjugate of 3+9i is 3-9i
So we have:
[(7+3i)*(3-9i)]/[3+9i)*(3-9i)] =
[21-63i+9i+27i^2]/[9-81i^2] =
[21-54i+(27*-1)]/[9-81*(-1)] =
(21-27-54i)/(9+81) =
(-6-54i)/90 = -1/15 - 3i/5 = = (-1/5)*(1/3 + 3i)
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