SOLUTION: Still having problems with graphing... Solve by graphing. 2x+y=5 3X-y=10 Here is what I have so far. y=3x-10 & y=-2x+5, but still do not know how to graph if that is cor

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson  -> Lesson -> SOLUTION: Still having problems with graphing... Solve by graphing. 2x+y=5 3X-y=10 Here is what I have so far. y=3x-10 & y=-2x+5, but still do not know how to graph if that is cor      Log On


   

Question 254836: Still having problems with graphing...
Solve by graphing.
2x+y=5
3X-y=10
Here is what I have so far. y=3x-10 & y=-2x+5, but still do not know how to graph if that is correct.
Answer by vksarvepalli(154) About Me  (Show Source):
You can put this solution on YOUR website!
you have y=3x-10 as one line
to graph it just find the intercepts or any two points
since to draw a line we need two points
so x intercept (put y=0) is 10/3
y intercept (put x=0) is -10
now the points are (10/3,0) and (0,-10)
now draw the line
similarly draw the other line both will intersect at a point that will give the values of x and y