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Prove by contradiction log2 11 is irrational. I'm a little stuck. Thank you.
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Let assume that is a rational number
= ,
where m and n are integer numbers. Then
= 11.
Raise both sides of this equation to degree n. You will get
= . (*)
But 2 and 11 are relatively prime numbers.
So, equality (*) CONTRADICTS to the basic theorem of arithmetic
about uniqueness of the decomposition of integer numbers into a product of primes.