SOLUTION: Please solve for x; (a)logx 121 = 2 (b) log4 1/256=x (c)log1/3 x=5 show steps please thanks!

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson  -> Lesson -> SOLUTION: Please solve for x; (a)logx 121 = 2 (b) log4 1/256=x (c)log1/3 x=5 show steps please thanks!      Log On


   

Question 1152203: Please solve for x;
(a)logx 121 = 2
(b) log4 1/256=x
(c)log1/3 x=5
show steps please thanks!
Found 2 solutions by ankor@dixie-net.com, MathTherapy:
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Please solve for x;
assume you mean
(a)log%28x%2C+%28121%29%29+=+2
put it in the exponent form
x%5E2+=+121
x+=+sqrt%28121%29
x = 11
:
(b) log%284%2C+%281%2F256%29%29+=+x
the exponent form
4%5Ex+=+%281%2F256%29
we know that 4*4*4*4 = 256 and that negative exponent gives the reciprocal
4%5E-4+=+1%2F256
x = -4
:
(c)log%281%2F3%2C+%28x%29%29+=+5
exponent equiv
%281%2F3%29%5E5+=+x
x = %281%2F3%29%2A%281%2F3%29%2A%281%2F3%29%2A%281%2F3%29%2A%281%2F3%29
x = 1%2F234

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Please solve for x;
(a)logx 121 = 2
(b) log4 1/256=x
(c)log1/3 x=5
show steps please thanks!
a) matrix%281%2C3%2C+log+%28x%2C+%28121%29%29%2C+%22=%22%2C+2%29

    ------ Converting to EXPONENTIAL form, and SOLVING

b) matrix%281%2C3%2C+log+%284%2C+%281%2F256%29%29%2C+%22=%22%2C+x%29                    

    ------ Converting to EXPONENTIAL form, and SOLVING

c)  matrix%281%2C3%2C+log+%281%2F3%2C+%28x%29%29%2C+%22=%22%2C+5%29

    -------- Converting to EXPONENTIAL form, and SOLVING