SOLUTION: I am having trouble with this problem, and I can't seem to figure where to start: Find the real numbers x and y that make the equation true. -3 + yi = x + 6i

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson  -> Lesson -> SOLUTION: I am having trouble with this problem, and I can't seem to figure where to start: Find the real numbers x and y that make the equation true. -3 + yi = x + 6i      Log On


   

Question 1040712: I am having trouble with this problem, and I can't seem to figure where to start:
Find the real numbers x and y that make the equation true.
-3 + yi = x + 6i
Found 3 solutions by richard1234, Boreal, ikleyn:
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
x and y are real, and the real and imaginary parts of the left-hand side and the right-hand sides must both be equal for the equation to be true.

Setting y = 6 and x = -3 achieves that result.

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
-3 + yi = x + 6i
x=-3
y=6
Complex numbers of the form a+bi require the constant a to match and the coefficient of the i to match.

Answer by ikleyn(52787) About Me  (Show Source):