SOLUTION: Solve each rational equation: 2x-1 over x^2+2x-8 plus 2 over x+4 = 1 over x-2 Thank you

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Question 1039271: Solve each rational equation:
2x-1 over x^2+2x-8
plus
2 over x+4
= 1 over x-2
Thank you

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
In pure text,
(2x-1)/(x^2+2x-8)+2/(x+4)=1/(x-2)


Rendered to appear %282x-1%29%2F%28x%5E2%2B2x-8%29%2B2%2F%28x%2B4%29=1%2F%28x-2%29

Factoring the quadratic denominator %282x-1%29%2F%28%28x%2B4%29%28x-2%29%29%2B2%2F%28x%2B4%29=1%2F%28x-2%29


First step is to multiply the left and right members by the simplest common denominator %28x%2B4%29%28x-2%29....

%282x-1%29%28x-2%29%2B2%28x-2%29=x%2B4


... then continue to simplify and solve for x.
Be sure to check if found values work in the original equation.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Solve each rational equation:
2x-1 over x^2+2x-8
plus
2 over x+4
= 1 over x-2
Thank you
%282x+-+1%29%2F%28x%5E2+%2B+2x+-+8%29+%2B+2%2F%28x+%2B+4%29+=+1%2F%28x+-+2%29
Factoring denominator x%5E2+%2B+2x+-+8, we get: %282x+-+1%29%2F%28x+%2B+4%29%28x+-+2%29+%2B+2%2F%28x+%2B+4%29+=+1%2F%28x+-+2%29, with matrix%281%2C3%2C+x+%3C%3E+-+4%2C+and%2C+x+%3C%3E+2%29
2x - 1 + 2(x - 2) = 1(x + 4) -------- Multiplying by LCD, (x + 4)(x - 2)
2x - 1 + 2x - 4 = x + 4
2x + 2x - 5 = x + 4
4x - 5 = x + 4
4x - x = 4 + 5
3x = 9
highlight_green%28matrix%281%2C3%2C+x+=+9%2F3%2C+or%2C+x+=+3%29%29