SOLUTION: Use Calculus. For what value of a is the following equation true? lim ((x+a)/(x-a))^x = e x->inf

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson  -> Lesson -> SOLUTION: Use Calculus. For what value of a is the following equation true? lim ((x+a)/(x-a))^x = e x->inf      Log On


   



Question 1030353: Use Calculus. For what value of a is the following equation true?
lim ((x+a)/(x-a))^x = e
x->inf

Found 2 solutions by Edwin McCravy, robertb:
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
matrix%282%2C1%2Clim%2C%22x-%3Eoo%22%29%28%28x%2Ba%29%2F%28x-a%29%29%5Ex%22%22=%22%22e

That will be true if and only if the 
limit of the natural log is 1, so we
reduce the problem to finding "a" if

matrix%282%2C1%2Clim%2C%22x-%3Eoo%22%29ln%28%28%28x%2Ba%29%2F%28x-a%29%29%5Ex%29%22%22=%22%221

matrix%282%2C1%2Clim%2C%22x-%3Eoo%22%29x%2Aln%28%28x%2Ba%29%2F%28x-a%29%29%22%22=%22%221

matrix%282%2C1%2Clim%2C%22x-%3Eoo%22%29ln%28%28x%2Ba%29%2F%28x-a%29%29%2F%281%2Fx%29%22%22=%22%221

Since matrix%282%2C1%2Clim%2C%22x-%3Eoo%22%29%28%28x%2Ba%29%2F%28x-a%29%29%22%22=%22%221
therefore matrix%282%2C1%2Clim%2C%22x-%3Eoo%22%29ln%28%28x%2Ba%29%2F%28x-a%29%29%22%22=%22%220
And also matrix%282%2C1%2Clim%2C%22x-%3Eoo%22%29%281%2Fx%29%22%22=%22%220

Both numerator and denominator approach 0, so
we can use L'Hopital's rule

matrix%282%2C1%2Clim%2C%22x-%3Eoo%22%29%28%282a%2F%28a%5E2-x%5E2%29%29%2F%28-1%2Fx%5E2%29%29%29 = 1

which simplifes to

matrix%282%2C1%2Clim%2C%22x-%3Eoo%22%29%28-2ax%5E2%2F%28a%5E2-x%5E2%29%29%29 = 1

That limit is 2a, so we have

2a+=+1

a+=+1%2F2

Edwin

Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
We will use the definition of e to evaluate this: lim%28n-%3Einfinity%2C+%281%2Blambda%2Fn%29%5E%28n%2Flambda%29%29+=+e
Now let w = x-a.
==> x+a = w+2a, w-%3E+infinity as x-%3Einfinity, and


= .
In the very last expression, the second limit lim%28w-%3Einfinity%2C+%281%2B%282a%29%2Fw%29%5Ea%29+=+1+, because %282a%29%2Fw+-%3E+0 as w approaches infinity, and a is a fixed constant that doesn't vary with w.
But , and hence 2a = 1, or a = 1/2.