Solver FIND inverse of complex number
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==section input Find inverse of *[input a=3] + *[input b=-4]i ==section solution perl print "The inverse of a number x is 1 divided by x: {{{inverse(x) = 1/x}}}. So, all we have to do, really, is to divide complex number 1=1+0i by {{{$a+$b*i}}}.<BR>\n"; solve( "complex_arithmetic", 1, 0, '/', $a, $b ); $z=1; ==section output z ==section check a=1 b=1 z=1 ==section practice perl $a = randint( -3, 3 ); $b = randint( -3, 3 );
