Tutors Answer Your Questions about Complex Numbers (FREE)
Question 1205575: Hi, I am having trouble with this question, and understanding the methodology.
B) Three impedances are connected in parallel. Z1 = 2-5j, Z2 = 6-3j, Z3 = 5j.
Find the equivalent admittance Y where :  .
Express the admittance in both rectangular and polar forms.
Click here to see answer by Edwin McCravy(20054)   |
Question 1205778: Hi, I have shown my working for the question below, am I on the right track?
〖Simplify 10〗^241 mod(13)
Fermat’s Little Theorem states:
a^(p-1)≡1mod(p)
Substitute:
10^12≡1mod(13)
By our multiplication theorem we know that if
10^12≡1mod(13)
Then
10^((12)A)≡(1)^A mod (13)
We want to get from a power of 12 up to around 241, and 12 x 20 = 240
10^(12)(20) ≡1^20 mod(13)
≡1mod(13)
So what we have so far is
10^241 mod(13)≡10^240×10^1 mod(13)
≡1×10mod(13)
≡10mod(13)
When 10^241is divided by 13, the remainder is 10
Thank you
Click here to see answer by ikleyn(52750)  |
Question 1205778: Hi, I have shown my working for the question below, am I on the right track?
〖Simplify 10〗^241 mod(13)
Fermat’s Little Theorem states:
a^(p-1)≡1mod(p)
Substitute:
10^12≡1mod(13)
By our multiplication theorem we know that if
10^12≡1mod(13)
Then
10^((12)A)≡(1)^A mod (13)
We want to get from a power of 12 up to around 241, and 12 x 20 = 240
10^(12)(20) ≡1^20 mod(13)
≡1mod(13)
So what we have so far is
10^241 mod(13)≡10^240×10^1 mod(13)
≡1×10mod(13)
≡10mod(13)
When 10^241is divided by 13, the remainder is 10
Thank you
Click here to see answer by math_tutor2020(3816) |
Question 1205778: Hi, I have shown my working for the question below, am I on the right track?
〖Simplify 10〗^241 mod(13)
Fermat’s Little Theorem states:
a^(p-1)≡1mod(p)
Substitute:
10^12≡1mod(13)
By our multiplication theorem we know that if
10^12≡1mod(13)
Then
10^((12)A)≡(1)^A mod (13)
We want to get from a power of 12 up to around 241, and 12 x 20 = 240
10^(12)(20) ≡1^20 mod(13)
≡1mod(13)
So what we have so far is
10^241 mod(13)≡10^240×10^1 mod(13)
≡1×10mod(13)
≡10mod(13)
When 10^241is divided by 13, the remainder is 10
Thank you
Click here to see answer by Edwin McCravy(20054) |
Question 1205868: Hi, So my question is:
A bag of lollies is shared. When shared equally among 4 people, there are 2 lollies left. When shared equally among 9 people, there are 5 lollies left. When shared equally among 7 people, there are 2 lollies left.
Determine the smallest possible number of lollies that could have been in the bag as well as the general solution.
I have tried a few different ways and get different answers.I either get 86 or 94. Can you help? Thank you
Click here to see answer by ikleyn(52750) |
Question 1205868: Hi, So my question is:
A bag of lollies is shared. When shared equally among 4 people, there are 2 lollies left. When shared equally among 9 people, there are 5 lollies left. When shared equally among 7 people, there are 2 lollies left.
Determine the smallest possible number of lollies that could have been in the bag as well as the general solution.
I have tried a few different ways and get different answers.I either get 86 or 94. Can you help? Thank you
Click here to see answer by Edwin McCravy(20054) |
Question 1205868: Hi, So my question is:
A bag of lollies is shared. When shared equally among 4 people, there are 2 lollies left. When shared equally among 9 people, there are 5 lollies left. When shared equally among 7 people, there are 2 lollies left.
Determine the smallest possible number of lollies that could have been in the bag as well as the general solution.
I have tried a few different ways and get different answers.I either get 86 or 94. Can you help? Thank you
Click here to see answer by mccravyedwin(405)  |
Question 1205868: Hi, So my question is:
A bag of lollies is shared. When shared equally among 4 people, there are 2 lollies left. When shared equally among 9 people, there are 5 lollies left. When shared equally among 7 people, there are 2 lollies left.
Determine the smallest possible number of lollies that could have been in the bag as well as the general solution.
I have tried a few different ways and get different answers.I either get 86 or 94. Can you help? Thank you
Click here to see answer by greenestamps(13195)  |
Question 1205951: Use De Moivres Theorem to simplify Power[\(40)cos\(40)Divide[\(40)5pi\(41),6]\(41)-sin\(40)Divide[\(40)5pi\(41),6]\(41)\(41),7].
I need help please, I have done some examples but keep getting stuck. Hopefully it comes across OK. Thank you Poss.
Click here to see answer by ikleyn(52750) |
Question 1206040: Without exp anding , prove that the following det er min atnts vanish ., |{{ b - c , c - a , c },{ c , b - x , a },{ c , a , c - x }}| = zero
Click here to see answer by math_tutor2020(3816) |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400, 5401..5445, 5446..5490, 5491..5535, 5536..5580, 5581..5625, 5626..5670, 5671..5715, 5716..5760, 5761..5805, 5806..5850, 5851..5895, 5896..5940, 5941..5985, 5986..6030, 6031..6075, 6076..6120, 6121..6165, 6166..6210, 6211..6255, 6256..6300, 6301..6345, 6346..6390, 6391..6435, 6436..6480, 6481..6525, 6526..6570, 6571..6615, 6616..6660, 6661..6705, 6706..6750, 6751..6795, 6796..6840, 6841..6885, 6886..6930, 6931..6975, 6976..7020, 7021..7065, 7066..7110, 7111..7155, 7156..7200, 7201..7245, 7246..7290, 7291..7335, 7336..7380
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