Tutors Answer Your Questions about Complex Numbers (FREE)
Question 58948: can you please help me understand how to simplify this problem (3+2i)(5-i)
i keep getting different answers each time i try it the first step that i did was to use the distributive property and then i got 15-3i+10i-2 then i simplified it and got 7i+13
Click here to see answer by mszlmb(115)   |
Question 58948: can you please help me understand how to simplify this problem (3+2i)(5-i)
i keep getting different answers each time i try it the first step that i did was to use the distributive property and then i got 15-3i+10i-2 then i simplified it and got 7i+13
Click here to see answer by adesouza(1) |
Question 59877: I understand that i have to multiply so that the denomomintor is 1 but I dont know how to do that because the denominator is a binomal.
Heres the problem,
 over
If you have the time it would be appreciated if you could sohw me the steps
Click here to see answer by funmath(2933) |
Question 59877: I understand that i have to multiply so that the denomomintor is 1 but I dont know how to do that because the denominator is a binomal.
Heres the problem,
over
If you have the time it would be appreciated if you could sohw me the steps
Click here to see answer by stanbon(75887) |
Question 59770:
I'm having an extremely hard time with Simplifying Complex Fractions! Thank you for helping me!!
1.) 4 + 2/x
_______
x/3+1/6
2.) 1
_______
K+2
________
5
______
K^2-4
3.) 16x^2-49y^2
___________
xy
___________
4 7
___ - ___
y x
4.) 5
____ -5
3r-1
_____________
5
____ +5
3r-1
5.) -5 2
____ + ____
x+5 x+2
_______________
2 -5
____ - _____
x+2 x+4
Click here to see answer by tutorcecilia(2152)  |
Question 61673: sir,
i am doing B.Sc(maths) 1st year at madurai kamaraj university through distance education. when i refered 11th books i couldn't understand some steps.
please explain me.
represent the complex number in the polar form
let z= -square root of 3+i
here a=-square root of 3,b=1
r=2
cos theta=-square root of 3/ 2
sin theta=1/2
tan theta=-1/square root of 3
tan theta=-tan(pi/6)(till this i understood)
here they have given theta =150(how this has came) explain me
the same doubt in another problem
the question is write the complex number 1-square root of 3(i)
r=2
cos theta=1/2
sintheta=-square root of 3/2
tan theta=-1/square root of 3
tan theta=tan(-1/square root of 3)
here they have given theta =-60 (explain me)
Click here to see answer by stanbon(75887) |
Question 63125: Given the zeros, 2-i, 1, 2, write a polynomial function of least degrees that has real coefficients, anda leading coefficient of 2.
I know it starts out like::: 2(x-1)(x-2)
But I get really confused on how to put the 2-i part in. I really would like your help, as my friends don't get it either.
Thank you very much,
E
Click here to see answer by Nate(3500) |
Question 63489: When we draw the complex number i as a point in the complex plane, its coordinates are
a. (0, i )
b. (1,0)
c. (0,1)
d. The number i cannot be drawn as a point in the complex plane
When we add the two complex numbers a + bi and c + di by representing them as points in the complex plane, then the sum is represented by
a. The corner of a rectangle whose other three corners are (0,0), (a,b), and (c,d)
b. The corner of a triangle whose other two corners are (a,b) and (c,d)
c. the corner of a parallelogram whose other three corners are (0,0), (a,b), and (c,d)
d. None of the above
Just like we do for the real numbers, we can draw a picture of the complex numbers simply by drawing a line.
a. True
b. False
The Division Algorithm for Polynomials and the Factor Theorem for Polynomials (which we proved when the polynomials have real number coefficients) are both TRUE even if the coefficients of the polynomials come from the complex numbers.
a True
b. False
Click here to see answer by stanbon(75887) |
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