Tutors Answer Your Questions about Complex Numbers (FREE)
Question 930626: Write the equation, in standard form, of a polynomial with real coefficients that has roots at 2, 1−2i, and 1+4i, and passes through the point (0,98).
Your answer should include only (decimal) numbers, the letter "x", and the characters "+", "-", and "^"
f(x)=___________
Click here to see answer by MathLover1(20849)   |
Question 932861: x=2+5i or x=2x-5i
Write a quadratic equation that has two solutions.
I believe I am supposed to FOIL this after I factor it, however I'm not quite sure of the process to get the answer to this question. Would I do (2x-5i)(2x+5i)? Or (x-2-5i)(x+2+5i)? Do I even need to do any of that?
Click here to see answer by josgarithmetic(39613) |
Question 935628: Question 1
Z1=3+2j Z2=1+7j
A. Find Z1xZ2
B. Find Z1/Z2
Question 2
Convert Z1 and Z2 into polar and find the following
A. Find Z1xZ2
B. Find Z1/Z2
Please answer in as much detail as possible and show all working for both questions.
Thank you
Click here to see answer by Fombitz(32388)  |
Question 937988: I'm trying to figure out how to find "Complex Zeros of Quadratic Functions" but the Holt McDougal video lesson isn't helping whatsoever and I've researched as much as I could. I'm trying to find the zeros of "f(x)=x˛+2x+3" and the video says the answer is x=6+2i√3. This involves imaginary numbers.
Click here to see answer by nerdybill(7384)  |
Question 937988: I'm trying to figure out how to find "Complex Zeros of Quadratic Functions" but the Holt McDougal video lesson isn't helping whatsoever and I've researched as much as I could. I'm trying to find the zeros of "f(x)=x˛+2x+3" and the video says the answer is x=6+2i√3. This involves imaginary numbers.
Click here to see answer by josgarithmetic(39613) |
Question 937988: I'm trying to figure out how to find "Complex Zeros of Quadratic Functions" but the Holt McDougal video lesson isn't helping whatsoever and I've researched as much as I could. I'm trying to find the zeros of "f(x)=x˛+2x+3" and the video says the answer is x=6+2i√3. This involves imaginary numbers.
Click here to see answer by MathTherapy(10549)  |
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