Tutors Answer Your Questions about Complex Numbers (FREE)
Question 188636: Does 2i times the square root of -4 equal -4?
I think 2i times the square root of -4 does equal -4, because the square root of -4 equals 2i and (2i)(2i) equals 4i^2. i^2 = -1 so (-1)(4)= -4.
So I am wondering if my solution of -4 correct?
Click here to see answer by ptaylor(2198)  |
Question 189153: This question came from an exam paper in Australia:
Solve: z^2=3+5i
I presume that the question requires an answer in the form z = a + bi
I have tried, but I end up getting a square root of a square root for an exact answer, or approx. +1.1897 or -1.1897 for b and approx. +2.1013 or -2.1013 for a.
I obtained this by letting z = a + bi, and therefore z^2 = a^2 + 2abi -b^2, and therefore a^2 - b^2 equals 3, and 2ab equals 5, and then solving these two simultaneous equations.
Is there a simpler way, please?
Click here to see answer by Alan3354(69443)  |
Question 190322: This is not the right category i don't think but i really need help with this problem. I got the answer: x^2+x+1+(x^3/x^4-x^2+1 ) <-- (this is the remainder)
here is the problem:
x^6+x^5+x^3+x+1/x^4-x^2+1
I keep getting the remainder wrong. the book says that it should be 2x^3 instead of x^3. how?
Click here to see answer by solver91311(24713)  |
Question 190827: In problems 11 and 12, use the fact that the load a beam with a rectangular cross section can support is jointly proportional to the beams width and the square of its depth and inversely proportional to it's length.
11. A beam 2 cm wide and 5cm deep can support a load of 630kg. What load can it support when turned on its side?
Click here to see answer by Mathtut(3670) |
Question 190888: In problems 11 and 12, use the fact that the load a beam with a rectangular cross section can support is jointly proportional to the beams width and the square of its depth and inversely proportional to it's length.
11. A beam 3 cm wide and 5cm deep can support a load of 630kg. What load can it support when turned on its side?
please please please explain what you are doing if you answer this problem. it is so confusing i cant even think of what to do.
Click here to see answer by solver91311(24713)  |
Question 190905: Hello. I am not positive I put in the right topic. We are learning complex algebraic fractions. I solved a problem, and I am not sure if i solved it correctly, and if I did I am not sure how to show the work for the check. the problem is x-1/x + 7/3x = 9/4x
we have to cancel the denominators by finding an LCD and multiplying by that.
EX: LCD for the above problem is 12x, so i would x x-1 x 12x and the x and 12 x simplify it to 12x-12.
The answer i got is 11/12, but I am not sure if it is correct.
If not, please provide help on solving it because I am quite confused, and if you don't mind please assist me in the check (if the correct solution is a fraction because my teacher goes too fast and never stops so I am not able to ask for help)
thank you so much for your help :)
~Katie
Click here to see answer by ankor@dixie-net.com(22740)  |
Question 191036: In problems 11 and 12, use the fact that the load a beam with a rectangular cross section can support is jointly proportional to the beams width and the square of its depth and inversely proportional to it's length.
11. A beam 2 cm wide and 5cm deep can support a load of 630kg. What load can it support when turned on its side?
please please please explain what you are doing if you answer this problem. it is so confusing i cant even think of what to do.
Click here to see answer by stanbon(75887) |
Question 191719: Hi please help me solve the following problems.Thanks in advance...
1)Multiply as indicated.If possible, simplify any radical expressions that appear in the product.
(4 + sqrt of 5)(10-3sqrt of 5)
2)Solve each radical expression.
x=(sqrt of 3x+7)-3
3)Find each product.Write imaginary results in the form a + bi.
(7-2i)(-3+6i)
Regards,
Kattie
Click here to see answer by Alan3354(69443)  |
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