SOLUTION: How would I use DeMoiver's Theorem to find 2 square roots of 16(cos330 + j sin330)in polar form?
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Question 986069
:
How would I use DeMoiver's Theorem to find 2 square roots of 16(cos330 + j sin330)in polar form?
Answer by
ikleyn(52781)
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See the lesson
How to take a root of a complex number
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Answer
. One root is
= 4*(cos(115°) + i*sin(115°)) (notice that 115° =
.330°).
The other root is
= 4*(cos(115°+180°) + i*sin(115°+180°)) = 4*(cos(295°) + i*sin(295°)). (Notice that 180° =
.360°).
Also notice that
=
.