SOLUTION: http://jasper.kaptest.com/content/media/94/124694.9.27391735-902d-4512-9abc-9d8f449e7b51.png In the figure above, four right triangles are formed by inscribing a square in the

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: http://jasper.kaptest.com/content/media/94/124694.9.27391735-902d-4512-9abc-9d8f449e7b51.png In the figure above, four right triangles are formed by inscribing a square in the      Log On


   

Question 955620: http://jasper.kaptest.com/content/media/94/124694.9.27391735-902d-4512-9abc-9d8f449e7b51.png

In the figure above, four right triangles are formed by inscribing a square in the circle with center C and adding four line segments tangent to circle C. Two sides of each triangle have a length of s, as shown. What is the circumference of the circle, in terms of s ?
2πs
4s
4s sqrt 2
4πs sqrt 2
4πs
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!

Adding those 4 tangents to the circle merely circumscribes a
larger square around the circle, and if you draw the diagonals of the
inner (smaller ) square, you see that S is also the radius of the
circle:

and since the circlumference of a circle is given by
C = 2pr, and since the radius
is S, we substitute S for r and get
C = 2pS
Edwin