SOLUTION: Can someone also tell me What are (a) the x-intercepts, (b) the y-intercepts and (c) the foci of the ellipse x^2/25 + y^2/36 = 1 (a)_________ (b)_________ (c)_________

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: Can someone also tell me What are (a) the x-intercepts, (b) the y-intercepts and (c) the foci of the ellipse x^2/25 + y^2/36 = 1 (a)_________ (b)_________ (c)_________      Log On


   



Question 94181This question is from textbook
: Can someone also tell me What are (a) the x-intercepts, (b) the y-intercepts and (c) the foci of the ellipse
x^2/25 + y^2/36 = 1
(a)_________
(b)_________
(c)_________
This question is from textbook

Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!

Can someone also tell me What are (a) the x-intercepts, 
(b) the y-intercepts and (c) the foci of the ellipse
x%5E2%2F25+%2B+y%5E2%2F36+=+1 
(a)_________
(b)_________
(c)_________

Principles you need to learn about the two forms of ellipses.

What is important at first is to observe whether the number
underneath the x² is greater than or less than the number
undernesth the y².  The larger of these is always a² amd the
smaller one is always b². 

Rule 1.

x%5E2%2Fa%5E2+%2B+y%5E2%2Fb%5E2+=+1  where a+%3E+b

represents an ellipse that looks like this ( 
without the pointy thingy.

x-intercepts (a,0) and (-a,0) 
y-intercepts (0,b) and (0,-b)

Now to find the foci, first you must
calculate c by the formula

c = ±sqrt%28a%5E2-b%5E2%29

for the x-values of the foci.

So the foci are (-c,0) and (c,0).

-------------------------------------

Rule 2.

x%5E2%2Fb%5E2+%2B+y%5E2%2Fa%5E2+=+1  where a+%3E+b

represents an ellipse that is shaped like a zero 0 

x-intercepts (b,0) and (-b,0) 
y-intercepts (0,a) and (0,-a)

Now to find the foci, first you must
calculate c by the formula

c = ±sqrt%28a%5E2-b%5E2%29

for the x-values of the foci.

So the foci are (0,c) and (0,-c).

-------------------------------------

Yours here is the second case since the number
under the y² is greater than the number under 
the x²:

x%5E2%2F25+%2B+y%5E2%2F36+=+1

so we use rule 2.

a%5E2=36 so a=6

b%5E2=25 so b=5


x%5E2%2F5%5E2+%2B+y%5E2%2F6%5E2+=+1  since 6+%3E+5

represents an ellipse that is shaped like a zero 0 

x-intercepts (5,0) and (-5,0) 
y-intercepts (0,6) and (0,-6)

Now to find the foci, first you must
calculate c by the formula

c = ±sqrt%286%5E2-5%5E2%29 = ±sqrt%2836-25%29 = ±sqrt%2811%29

or about ±3.3

for the x-values of the foci.

So the foci are (0,sqrt%2811%29) and (0,-sqrt%2811%29),
or about (0,3.3) and (0,-3.3)
 
  
Here's the graph. The foci are marked with little short lines:

Edwin