SOLUTION: what is the answer of this given complex fraction (x+2)/[x(x-1)]+(1)/(x+1)/(x)/[(2x+1)(x-1)]+(1)/(x-1)?

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: what is the answer of this given complex fraction (x+2)/[x(x-1)]+(1)/(x+1)/(x)/[(2x+1)(x-1)]+(1)/(x-1)?      Log On


   

Question 885810: what is the answer of this given complex fraction (x+2)/[x(x-1)]+(1)/(x+1)/(x)/[(2x+1)(x-1)]+(1)/(x-1)?
Answer by josgarithmetic(39613) About Me  (Show Source):
You can put this solution on YOUR website!
The toughest part is that middle summand. Use division strictly from left to right to recompose that expression part.

(1)/(x+1)/(x)/[(2x+1)(x-1)]
Let me change the grouping symbols so rendering will work.


%281%29%2F%28x%2B1%29%2F%28x%29%2F%28%282x%2B1%29%28x-1%29%29

%281%2F%28x%28x%2B1%29%29%29%2F%28%282x%2B1%29%28x-1%29%29, note that the last two binomial factors are strictly associated and must act as a single number!!!

1%2F%28x%28x%2B1%29%28%282x%2B1%29%28x-1%29%29%29, and NOW that association is not strict within the denominator...

1%2F%28x%28x%2B1%29%282x%2B1%29%28x-1%29%29

That was JUST for the second fraction and not the first fraction nor third fraction. Simplifying the whole given expression should be much easier now.