SOLUTION: (a-bi) (a+bi) The i's are imaginary, you have to multiply,

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: (a-bi) (a+bi) The i's are imaginary, you have to multiply,       Log On


   

Question 834485: (a-bi) (a+bi)

The i's are imaginary, you have to multiply,
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
(a-bi)(a+bi)

a(a+bi)-bi(a+bi)

a(a)+a(bi)-bi(a)-bi(bi)

a^2+abi-abi-(bi)^2

a^2+abi-abi-b^2(i^2)

a^2+abi-abi-b^2(-1)

a^2+abi-abi+b^2

a^2+b^2

=======================================================

So,

(a-bi)(a+bi) = a^2+b^2