SOLUTION: Divide and express in standard form 2/3-i This is what I tried (2)/(3-I) . (3+I)/(3+I) 2/3-I = 2/3-I . I/I = 2I/3I+I^2 = 2I/+4 = 2I/3 = 2/2I = i

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: Divide and express in standard form 2/3-i This is what I tried (2)/(3-I) . (3+I)/(3+I) 2/3-I = 2/3-I . I/I = 2I/3I+I^2 = 2I/+4 = 2I/3 = 2/2I = i      Log On


   

Question 800834: Divide and express in standard form 2/3-i
This is what I tried
(2)/(3-I) . (3+I)/(3+I)
2/3-I = 2/3-I . I/I = 2I/3I+I^2 = 2I/+4 = 2I/3 = 2/2I = i
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
I could not quite follow what you did here, anyway:
:
Divide and express in standard form 2/3-i
2%2F%28%283-i%29%29*%28%283%2Bi%29%29%2F%28%283%2Bi%29%29 = %282%283%2Bi%29%29%2F%28%289+%2B3i+-+3i+-i%5E2%29%29 = %28%286%2B2i%29%29%2F%28%289+-+%28-1%29%29%29 = %28%286%2B2i%29%29%2F%28%289+%2B+1%29%29%29 = %28%286%2B2i%29%29%2F%2810%29
reduce the fraction, factor out 2
%28%283%2Bi%29%29%2F5