Question 615287: Solve by completing the square:10x=3x^2-1
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Solve by completing the square:10x=3x^2-1
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3x^2 -10x -1 = 0
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3(x^2- (10/3)x + ?) = 1/3 + 3?
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3(x^2 - (10/3)x + (5/3)^2) = (1/3) + 3(5/3)^2
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3(x-(5/3)^2 = (1/3) + (25/3)
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(x-(5/3))^2 = (26/9)
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x-(5/3) = sqrt(26)/3 or x - (5/3) = -sqrt(26)
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x = (-5+sqrt(26))/3 or x = (5-sqrt(sqrt(26))/3
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Cheers,
Stan H.
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