SOLUTION: I would like to verify that I have done this correctly. Divide the complex number (1-3i)/(3+2i) =((1-2i)(3-2i))/((3+2i)(3-2i)) = (3-8i)/9 =1/3+8i/9. How did I do?

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: I would like to verify that I have done this correctly. Divide the complex number (1-3i)/(3+2i) =((1-2i)(3-2i))/((3+2i)(3-2i)) = (3-8i)/9 =1/3+8i/9. How did I do?      Log On


   

Question 61174: I would like to verify that I have done this correctly. Divide the complex number (1-3i)/(3+2i)
=((1-2i)(3-2i))/((3+2i)(3-2i))
= (3-8i)/9
=1/3+8i/9.
How did I do?
Answer by tutorcecilia(2152) About Me  (Show Source):
You can put this solution on YOUR website!
(1-3i)/(3+2i)
%28%281-3i%29%283-2i%29%2F%283%2B2i%29%283-2i%29%29
%28+%283-2i-9i%2B6i%5E2%29%2F%289-6i%2B6i-4i%5E2%29%29 [Use the FOIL method to multiply. Remember that i^2=-1]
.
%28+%283-11i%2B6i%5E2%29%2F%289-4i%5E2%29%29 [simplify]
%28+%283-11i%2B6%28-1%29%29%2F%289-4%28-1%29%29%29[i^2=-1]
%28+%283-11i-6%29%29%2F%289%2B4%29%29%29
%28+%28-3-11i%29%29%2F%2813%29%29%29