SOLUTION: can someone help me by monday plss? rly need help! thank you! simplify the complex fraction. 2. p^3q^2/m^5n^7 over p^2q^5/m^2n

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: can someone help me by monday plss? rly need help! thank you! simplify the complex fraction. 2. p^3q^2/m^5n^7 over p^2q^5/m^2n      Log On


   



Question 473444: can someone help me by monday plss? rly need help! thank you!
simplify the complex fraction.
2. p^3q^2/m^5n^7 over p^2q^5/m^2n

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
%28p%5E3q%5E2%2Fm%5E5n%5E7%29%2F%28p%5E2q%5E5%2Fm%5E2n%29


Write as a division of numerator ÷ debominator:

%28p%5E3q%5E2%2Fm%5E5n%5E7%29%22%F7%22%28p%5E2q%5E5%2Fm%5E2n%29

Invert the second and change ÷ to ×

%28p%5E3q%5E2%2Fm%5E5n%5E7%29%22%D7%22%28m%5E2n%2Fp%5E2q%5E5%29

Indicate the multiplication of numerators and denominators:

p%5E3q%5E2m%5E2n%2Fm%5E5n%5E7p%5E2q%5E5

Since there is a p³ on the TOP and a p² on the BOTTOM, we
subtract the exponents 3-2 and get 1, so we write p1
or just p on the top because the larger exponent was p³ and it 
was on the TOP, and remove the p² on the BOTTOM:

pq%5E2m%5E2n%2Fm%5E5n%5E7q%5E5

Since there is a q⁵ on the BOTTOM and a q² on the TOP, we
subtract the exponents 5-2 and get 3, so we write q³ on the 
BOTTOM because the larger exponent was q⁵ and it 
was on the BOTTOM, and remove the q² on the TOP:

pm%5E2n%2Fm%5E5n%5E7q%5E3

Since there is an m⁵ on the BOTTOM and a m² on the TOP, we
subtract the exponents 5-2 and get 3, so we write m³ on the 
BOTTOM because the larger exponent was m⁵ and it 
was on the BOTTOM, and remove the m² on the TOP:

pn%2Fm%5E3n%5E7q%5E3

Since there is an n⁷ on the BOTTOM and a n1 on the TOP, we
subtract the exponents 7-1 and get 6, so we write n⁶ on the 
BOTTOM because the larger exponent was n⁷ and it 
was on the BOTTOM, and remove the n on the TOP:

p%2Fm%5E3n%5E6q%5E3

Edwin